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146b^2-2=-3b
We move all terms to the left:
146b^2-2-(-3b)=0
We get rid of parentheses
146b^2+3b-2=0
a = 146; b = 3; c = -2;
Δ = b2-4ac
Δ = 32-4·146·(-2)
Δ = 1177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{1177}}{2*146}=\frac{-3-\sqrt{1177}}{292} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{1177}}{2*146}=\frac{-3+\sqrt{1177}}{292} $
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